Question

Resolva as seguintes equações do 2 grau:

A)3x²+3=-2x²+12
B)x²+26=1

Answer 1

Resposta:

Explicação passo-a-passo:

$A) 3x^2+3=-2x^2+12\\3x^2+2x^2=12-3\\5x^2=9\\x^2=\frac{9}{5}\\\\x=^+_-\sqrt{\frac{9}{5}}=> x=^+_-\frac{3}{\sqrt{5}}$

$B)x^2+26=1\\x^2=1-26\\x^2=-25\\x=^+_-\sqrt{(-1)*25}\\\\x=^+_-i5$