Matemática, perguntado por lidianeelopess, 11 meses atrás

Resolva as seguintes equaçoes do 2 grau a)2x^2-8x+8=0 b)x^2-8x+12=0 c)x^2+2x-8=0 d)3x^2-7x+2=0 e)4x^2-8x+4=0
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Soluções para a tarefa

Respondido por luciatmlopes
0

Resposta:

a)2x^2-8x+8=0

∆=b^2-4ac

∆=(-8)^2-4.(2).8

∆=64-64=0

x= -b+-√∆/2a

x= -(-8+√0)/2.2

x=8/4

x1=2

x2= -2

B)x^2-8x+12=0

∆=b^2-4ac

∆=(-8)^2-4.(1).(12)

∆64-48=16

x= -b _+✓∆\2.a

x=-(-8)+✓16/2

x=8+4/2

x1= 8+4/2 =12/2= 6

x2=8-4/2=4/2=2

C)x^2+2x-8=0

∆=(2)^2-4.(1).(-8)

∆= 4+32=36

x= - (2)+ou -✓36/2

x1= -2+6/2 =4/2=2

x2= -2-6/2= -8/2= -4

D)3x^2-7x+2=0

∆=b^2-4ac

∆=(-7)^2-4(3).(2)

∆=49-24=25

x= -b+✓∆\2a

x= -(-7)+✓25/6

x1= 7+5/6=12/6=2

x2=7-5/6=2/6=1/3

E)4x^2-8x+4=0

∆=b^2-4ab

∆(-8)^2-4(4).(4)

∆=64-64=0

x= -b+√∆\2a

x= -(-8)+√0/8

x1=8+0/8=1

x2=8-0/8= -1


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