Matemática, perguntado por larissadahlia112, 5 meses atrás

Resolva as seguintes equações do 2 grau

Anexos:

Soluções para a tarefa

Respondido por SocratesA
3

Resolvidas as equações do segundo grau, as raízes obtidas das mesmas foram:

a) (0 ; 7)\\\\b) (0 ; -5)\\\\c) (0 ; 9 / 4)\\\\d) (0 ; -5 / 3)\\\\e)  (0 ; 3)\\\\f) (0 ; 1 /5)\\\\g) (0 ; 7 / 2)\\\\h) (0 ; -5)\\\\

Resolva as seguintes equações do segundo grau.

a) x^2 - 7x = 0\\b) x^2 + 5x = 0\\c) 4x^2 - 9x = 0\\d) 3x^2 + 5x = 0\\e) 4x^2 - 12x = 0\\f) 5x^2 + x = 0\\g) 2x^2 = 7x\\h) 2x^2 + 10x = 0 \\

As equações do segundo grau apresentadas se encontram escritas na

forma incompleta, e para resolvê-las temos que colocar a variável x" em

evidência.

a) x^2 - 7x = 0\\\\x.(x - 7) = 0\\\\x = 0\\\\ou\\\\x - 7 = 0\\\\x = 7\\\\====\\

b) x^2 + 5x = 0\\\\x.(x + 5) = 0\\\\x = 0\\\\ou\\\\x + 5 = 0\\\\x = -5\\\\====\\

c) 4x^2 - 9x = 0\\x.(4x - 9) = 0\\\\x = 0\\\\ou\\\\4x - 9 = 0\\\\4x = 9\\\\x = 9 / 4\\\\=====\\

d) 3x^2 + 5x = 0\\\\x.(3x + 5) = 0\\\\x = 0\\\\ou\\\\3x + 5 = 0\\\\3x = -5\\\\x = -5 / 3\\\\=====\\\\

e) 4x^2 - 12x = 0\\\\4x.(x - 3) = 0\\\\4x = 0\\\\x = 0 / 4\\\\x = 0\\\\ou\\\\x - 3 = 0\\\\ x = 3\\\\=====

f) 5x^2 + x = 0\\\\x.(5x + 1) = 0\\\\x = 0\\\\ou\\\\5x - 1 = 0\\\\5x = 1\\\\x = 1 / 5\\\\=====

g) 2x^2 = 7x\\\\2x^2 - 7x = 0\\\\x.(2x - 7) = 0\\\\x = 0\\\\ou\\\\2x - 7 = 0\\\\2x = 7\\\\x = 7 / 2\\\\=====\\\\

h) 2x^2 + 10x = 0\\ \\2x.(x + 5) = 0\\\\2x = 0\\\\x = 0 / 2\\\\x = 0\\\\\ou\\\\x + 5 = 0\\\\ x = -5\\\\=====

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