Resolva as seguintes equações: a) 8 (x+3)!/(x+4)!=2
B) n!/(n-2)!=42
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a)
8*(x + 3)!/(x + 4)! = 2
(x + 3)!/(x + 4)! = 2/8 = 1/4
inverse
(x + 4)!/(x + 3)! = 4
x + 4 = 4
x = 0
b)
n!/(n - 2)! = 42
n*(n - 1) = 42
n² - n - 42 = 0
(n - 7)*(n + 6) = 0
n = 7
a)
8*(x + 3)!/(x + 4)! = 2
(x + 3)!/(x + 4)! = 2/8 = 1/4
inverse
(x + 4)!/(x + 3)! = 4
x + 4 = 4
x = 0
b)
n!/(n - 2)! = 42
n*(n - 1) = 42
n² - n - 42 = 0
(n - 7)*(n + 6) = 0
n = 7
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