Question

resolva as seguintes equações
a)4X-1=3(X-1)
b)3(X-2)=2X-4
c)2(X-1)=3X+4
d)3(X-1)-7-15
e)7(X-4)=2X-3
f)3(X-2)=4(3-X)
g)3(3X-1)=2(3X+2)
h)7(X-2)=5(X+3)
i)4(X+10)-2(X-5)=0
Me ajuda Pfv haaaaa​

Answer 1

Resposta:

a)4X-1=3(X-1)

$4x - 1 = 3x - 3 \\ 4x - 1 - 3x + 3 = 0 \\ x + 2 = 0 \\ x = - 2$

b)3(X-2)=2X-4

$3x - 6 = 2x - 4 \\ 3x - 6 - 2x + 4 = 0 \\ x - 2 = 0 \\ x = 2$

c)2(X-1)=3X+4

$2x - 2 = 3x + 4 \\ 2x - 2 - 3x - 4 = 0 \\ - x - 6 = 0 \\ - x = 6 \times ( - 1) \\ x = - 6$

d)3(X-1)-7-15

$3x - 3 - 7 - 15 = 0 \\ 3x - 25 = 0 \\ 3x = 25 \\ \\ x = \frac{25}{3}$

e)7(X-4)=2X-3

$7x - 28 = 2x - 3 \\ 7x - 28 - 2x + 3 = 0 \\ 5x - 25 = 0 \\ 5x = 25 \div (5) \\ x = 5$

f)3(X-2)=4(3-X)

$3x - 6 = 12 - 4x \\ 3x - 6 - 12 + 4x = 0 \\ 7x - 18 = 0 \\ 7x = 18 \\ \\ x = \frac{18}{7}$

g)3(3X-1)=2(3X+2)

$9x - 3 = 6x + 4 \\ 9x - 3 - 6x - 4 = 0 \\ 3x - 7 = 0 \\ 3x = 7 \\ \\ x = \frac{7}{3}$

h)7(X-2)=5(X+3)

$7x - 14 = 5x + 15 \\ 7x - 14 - 5x - 15 = 0 \\ 2x - 29 = 0 \\ 2x = 29 \\ \\ x = \frac{29}{2}$

i)4(X+10)-2(X-5)=0

$4x + 40 - 2x + 10 = 0 \\ 2x + 50 = 0 \\ 2x = - 50 \div (2) \\ x = - 25$