Question

Resolva as seguintes equações:

a) 4x -1= 3 (x-1)
b) 3 (x-2)= 2x -4
c) 2 (x-1) 3x +4
d) 3 (x-1) -7= 15
e) 7 (x-2)= 4 (3-x)
f) 3 (x-2)= 4 (3-x)
g) 3 (3x -1) -2 (3x +2)
h) 7 (x-2)= 5 (x+3)
i) 3 (2x -1)= -2 (x+3)
j) 5x -3 (x+2)= 15
k) 2x +3x+9= 8 .(6-x)
l) 4 (x+10)= 2 (x-5)0
m)3 (2x+3) -4 (x-1)= 3
n)7 (x-1) -2 (X-5)= X-5
o) 2 (3-x)= 3 (x-4) +15
p)3 (5-x) -3 (1-2x)= 42
q) (4x+6) -2x= (x-6) +10+14
r) (x-3) - (x+2) +2 (x-1) -5= 0
s)3x -2 (4x-3)= 2-3 (x-1)
t) 3 (x-1) - (x-3) +5 (x-2)= 18
u) 5 (x-3) -4 (x+2)= 2+3 (1-2x)

Answer 1

Resposta:

$4x-1=3\left(x-1\right)\quad :\quad x=-2\\\\3\left(x-2\right)=2x-4\quad :\quad x=2\\\\2\left(x-1\right)\cdot \:3x+4=6x\left(x-1\right)+4\\\\3\left(x-1\right)-7=15\quad :\quad x=\frac{25}{3}\\\\7\left(x-2\right)=4\left(3-x\right)\quad :\quad x=\frac{26}{11}\quad \\\\3\left(x-2\right)=4\left(3-x\right)\quad :\quad x=\frac{18}{7}\\\\3\left(3x-1\right)-2\left(3x+2\right)=3x-7\\\\7\left(x-2\right)=5\left(x+3\right)\quad :\quad x=\frac{29}{2}$

$3\left(2x-1\right)=-2\left(x+3\right)\quad :\quad x=-\frac{3}{8}\\\\5x-3\left(x+2\right)=15\quad :\quad x=\frac{21}{2}\\\\2x+3x+9=8\left(6-x\right)\quad :\quad x=3$

$4\left(x+10\right)=2\left(x-5\right)\cdot \:0\quad :\quad x=-10\\\\3\left(2x+3\right)-4\left(x-1\right)=3\quad :\quad x=-5\\\\7\left(x-1\right)-2\left(x-5\right)=x-5\quad :\quad x=-2\\\\2\left(3-x\right)=3\left(x-4\right)+15\quad :\quad x=\frac{3}{5}\\\\3\left(5-x\right)-3\left(1-2x\right)=42\quad :\quad x=10\\\\\left(4x+6\right)-2x=\left(x-6\right)+10+14\quad :\quad x=12$

$\left(x-3\right)-\left(x+2\right)+2\left(x-1\right)-5=0\quad :\quad x=6\\\\3x-2\left(4x-3\right)=2-3\left(x-1\right)\quad :\quad x=\frac{1}{2}\\\\3\left(x-1\right)-\left(x-3\right)+5\left(x-2\right)=18\quad :\quad x=4\\\\5\left(x-3\right)-4\left(x+2\right)=2+3\left(1-2x\right)\quad :\quad x=4$

Explicação passo-a-passo: