Question

resolva as seguintes adições algébricas envolvendo radicais

Answer 1

a) $12\sqrt{25}-6\sqrt{25}+4\sqrt{25}=10\sqrt{25}=10.5=50$

b) $8\sqrt{100}+20\sqrt{100}-4\sqrt{100}=24\sqrt{100}=24.10=240$

c) $\sqrt{64}+12\sqrt{64}-10\sqrt{64}=3\sqrt{64}=3.8=24$

d) $\sqrt{121}+4\sqrt{121}-3\sqrt{121}=2\sqrt{121}=2.11=22$

e) $15\sqrt{144}+14\sqrt{144}-8\sqrt{144}=21\sqrt{144}=21.12=252$