Question

RESOLVA AS SEGUINTE EQUAÇÃO
$log(x + 2) + log(x + 3) = log12$
$log_{2}(3x + 10) - log_{2}x = log_{2}5$
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Answer 1

$(x + 2)(x + 3) = 12 \\ {x}^{2} + 2x + 3x + 6 = 12 \\ {x}^{2} + 5x - 6 = 0 \\ \\ Δ = {b}^{2} - 4ac \\ \\ x = \frac{ - b± \sqrt{Δ} }{2a} \\ \\ x1 = - 6 \\ x2 = 1$

$\frac{3x + 10}{x} = 5 \\ 3x + 10 = 5x \\ 2x = 10 \\ x = 5$