Question

Resolva as questões e quando necessário aplique as regras de sinais

a)³√125+√81=
b)_√16(elevado a quatro) .√100 +12=
c)2(elevado a quatro) . 2² . 2¹=
d)5².5².5²=
e)10° + 5°+100¹ -100=
f)25¹°÷ 25(elevado a 8)=
g)100²°÷ 100¹° ÷100(elevado a 8)=
h 12+5² -32-2=
i)2³-5°+100°-3=
j)2³-5°+100°-3=
k) [ (10¹+2³+7°)]. (√999¹°=
l)[ 100÷ 5.(-1)+1.000°+20]=

Answer 1

a)25+9=36
b)16.10+12=16.22=352
c)16.4.2=128
d)25.25.25=15.625
e)1+1+100-100=2
f)25(elevado á 2)=125
g)100(elevado á 2)=100000
h)12+25-32-2=37-30=7
i)8-1+100-3=7-97=-90
j)8-1+100-3=7-97=-90

Answer 2

a) ³√125 + √81
$\sqrt[3]{5^3} + 9 \\ \\ 5 + 9 \\ \\ 14$

b) -√16^4 * √100 + 12
-16^2 * 10 + 12
-256 * 10 + 12
-2560 + 12
-2548

c) 2^4 * 2² * 2¹
2^7
128

d) 5² * 5² * 5²
5^6
15625

e) 10° + 5° + 100¹ - 100
1 + 1 + 100 - 100
2 + 0
2

f) 25¹°÷ 25^8
25^2
625

g) 100²°÷ 100¹° ÷ 100^8
100^2
10.000

h) 12 + 5² - 32 - 2
12 + 25 - 34
37 - 34
3

i) 2³ - 5° + 100° - 3
8 - 1 + 1 - 3
8 + 0 - 3
5

j) 2³ - 5° + 100° - 3
8 - 1 + 1 - 3
8 + 0 - 3
5

k) [(10¹ + 2³ + 7°)] * (√999¹°)
[(10 + 8 + 1)] * ???

l) [100 ÷ 5 * (-1) + 1.000° + 20]
[20 * (-1) + 1 + 20]
-20 + 21
1

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