Question

resolva as potencias abaixo pela decomposição da soma de dois termos A,25 ao quadrado B,23 ao quadrado C,26 ao Quadrado

Answer 1

A 25²=625
B 23²=529
C 26²=676
essas são as respostas

Answer 2

$\boxed{(a+b)^2=a^2+2ab+b^2}$

A) 
$25^2=\\(5+20)^2=\\5^2+2\cdot5\cdot20+20^2=\\25+200+400=\\625$

B)
$23^2=\\(3+20)^2=\\3^2+2\cdot3\cdot20+20^2=\\9+120+400=\\529$

C)
$26^2=\\(6+20)^2=\\6^2+2\cdot6\cdot20+20^2=\\36+240+400=\\676$