Question

Resolva as inequações exponenciais abaixo : a)( ⅓)^3x-1≥ 1

Answer 1

1/3^3x-1 $\geq$ 1

3^-3x+1  $\geq$  3^0

-3x + 1  $\geq$  0

-3x  $\geq$  -1

x $\leq$   1/3

Answer 2

Explicação passo-a-passo:

$( \dfrac{1}{3} ) {}^{3x - 1} \geqslant 1$

$( \dfrac{1}{3} ) {}^{3x - 1} \geqslant ( \dfrac{1}{3} ) {}^{0}$

$3x - 1 \leqslant 0$

$3x \leqslant 0 + 1$

$3x \leqslant 1$

$x \leqslant \dfrac{1}{3}$