Question

resolva as inequaçoes a seguir :
2x -2 > x+1

(x-4)/2 + (x-3)/3 < x-4

(x-4)/2 > x- 1/2

Answer 1

2x -2 > x+1
2x -x > 1 +2
x > 3
S= {3} 

(x-4)/2 + (x-3)/3 < x-4    mmc de 2 e 3= 6
[3.(x-4) + 2.(x-3) < 6.(x-4)]/6
[3x -12  + 2x -6 < 6x -24]/6   elimina o denominador 6
3x -12 + 2x -6 < 6x -24
3x +2x -6x < -24 +12 +6
5x -6x < -24 +18
-x < - 6.(-1)
x > +6
S= {6}

(x-4)/2 > x- 1/2     mmc=2
(x-4 > 2x -1)/2    elimina o denominador 2
x-4 > 2x -1
x -2x > -1 +4
-x > +4.(-1)
+x < -4
S{-4}