Question

resolva as inequação a) senx<0 b) senx>√3/2 c) senx<1

Answer 1

a) senx<0
      
x<0+2kπ
x<π+2kπ
x<2π+2kπ

S={x∈lR/π+2kπ<x<2π+2kπ, com k∈Z}

b) sen x>√3/2

x>π/3+2kπ
x>2π/3+2kπ

S={x∈lR/π/3+2kπ<x<2π/3+2kπ, com K∈Z}

b)

senx<1

x<π/2+2kπ

S={x∈lR/x≠π/2+2kπ, com K∈Z}