Question

Resolva as funções do segundo grau:
A) f(x)=-3x(ao quadrado) +x -1=0
B)f(x)=-x(ao quadrado)+4=0
C)f(x)=x(ao quadrado)+2x+1=0

Answer 1

a) $-3x² + x - 1 x= \frac{-1 +-\sqrt{1-4.-3.-1} }{-6} \\ x= \frac{-1 +- \sqrt{-11} }{-6} = x1 = \frac{-1 +\sqrt{-11[tex]</p><p></p><p>b) 0 = -x^{2}  + 4\\x = \frac{-4 +-\sqrt{16-4.-1} }{-2} \\x = \frac{-4+-\sqrt{20} }{-2} \\x1 = \frac{-4+\sqrt{20} }{-2} \\x2 = \frac{-4-\sqrt{20} }{-2}$} }{-6} \\  x2 = \frac{-1 -\sqrt{-11} }{-6}[/tex]

c) $x + 2x + 1 = 0x = \frac{-2 +-\sqrt{4-4.1.1} }{2}\\x = \frac{-2+-\sqrt{0} }{2} \\x1 = \frac{-2+\sqrt{0} }{2} = - 1\\x2 = \frac{-2-\sqrt{0} }{2} = -1$