Question

Resolva as frações usando bhaskara


a) x² + 3x - 4 = 0

b) x² - 4x - 9 = 0

c) x² - x + 6 = 0

d) x² - 7x + 6 = 0
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Answer 1

Explicação passo-a-passo:

a) x² + 3x - 4 = 0

∆ = 3² - 4 . -4

∆ = 9 + 16

∆ = 25

x = -3±5/2

x' = -8/2 = -4

x' = -8/2 = -4x'' = 2/2 = 1

b) x² - 4x - 9 = 0

∆ = 4² - 4 . -9

∆ = 16 + 36

∆ = 52

x = 4±√52/2

√52 = 2√13

x' = 4-2√13/2 = 2 - √13

x' = 4-2√13/2 = 2 - √13x'' = 4+2√13/2 = 2 + √13

c) x² - x + 6 = 0

∆ = 1² - 4 . 6

∆ = 1 - 24

∆ = -23

x = 1±√-23/2

x' = (1 - √23i)/2

x' = (1 - √23i)/2x'' = (1 + √23i)/2

d) x² - 7x + 6 = 0

∆ = 7² - 4 . 6

∆ = 49 - 24

∆ = 25

x = 7±5/2

x' = 2/2 = 1

x' = 2/2 = 1x'' = 12/2 = 6

Espero Ter Ajudado !!