Question

resolva as fórmulas de Bhaskara
a)x²-4x-5=0

b)-x²+x+12=0

c)-x²+6x-5=0

d)6 x²+x-1=0

me ajudem urgenteeee​

Answer 1

Explicação passo-a-passo:

x² - 4x - 5 = 0

a= 1; b = -4; c = -5

D = -4² - 4 . 1 . (-5)

D = 16 + 20

D = 36

x' = -(-4) + 6

2 . 1

x' = 4 + 6

2

x' = 10

2

x' = 5

x" = -(-4) - 6

2 . 1

x" = 4 - 6

2

x'' = -2

2

x'' = -1

b)

-x² + x + 12 = 0

a= -1; b = 1; c = 12

D = 1² - 4 . -1 . 12

D = 1 + 48

D = 49

x' = -1 + 7

2 . (-1)

x' = -1 + 7

-2

x' = 6

-2

x' = -3

x" = -1 - 7

2 . (-1)

x" = -1 - 7

-2

x'' = -8

-2

x'' = 4

c)

-x² + 6x - 5 = 0

a= -1; b = 6; c = -5

D = 6² - 4 . -1 . (-5)

D = 36 - 20

D = 16

x' = -6 + 4

2 . (-1)

x' = -6 + 4

-2

x' = -2

-2

x' = 1

x" = -6 - 4

2 . (-1)

x" = -6 - 4

-2

x'' = -10

-2

x'' = 5

d)

6x² + x - 1 = 0

a= 6; b = 1; c = -1

D = 1² - 4 . 6 . (-1)

D = 1 + 24

D = 25

x' = -1 + 5

2 . 6

x' = -1 + 5

12

x' = 4

12

x' = 1/3

x" = -1 - 5

2 . 6

x" = -1 - 5

12

x'' = -6

12

x'' = -1/2