Resolva as expressões numéricas das potências A) (1/2)²+(1/3)²= B) (2/3)-(1/5)³= C) 3²-(3/2)²= D) (1/3)²:2/9-1/6= E)(3/8)*(4/5)²+(1/6)²= F) [(1/4)²+(1/2)³]=
isabelleventura1:
Mim ajudem!
Soluções para a tarefa
Respondido por
0
A) (1/2)²+(1/3)²=
1/4 + 1/9 = mmc = 36
9/36 + 4/36 =
9 + 4 / 36 =
13/36
B) (2/3)-(1/5)³=
2/3 - 1/125 = mmc 375
250/375 - 3/375 =
250 - 3 / 375 =
247 / 375
C) 3²-(3/2)²=
9 - 9/4 = mmc 4
36/4 - 9/4 =
36 - 9 /4 =
27 / 4
D) (1/3)²:2/9-1/6=
1/9 : 2/9 - 1/6 = mmc 18
2/18 : 4/18 - 3/18 =
2 : 4 - 3 /18 =
0,5 -3/18=
2,5/18
E)(3/8)*(4/5)²+(1/6)²=
3/8 . 16/25 + 1/36 =
48/200 + 1/36 =
12/50 + 1/36 = mmc 900
216/900 + 25/900 =
216 + 25/900 =
241 / 900 =
F) [(1/4)²+(1/2)³]=
1/16 + 1/8 = mmc 16
1/16 + 2/16 =
3/16
1/4 + 1/9 = mmc = 36
9/36 + 4/36 =
9 + 4 / 36 =
13/36
B) (2/3)-(1/5)³=
2/3 - 1/125 = mmc 375
250/375 - 3/375 =
250 - 3 / 375 =
247 / 375
C) 3²-(3/2)²=
9 - 9/4 = mmc 4
36/4 - 9/4 =
36 - 9 /4 =
27 / 4
D) (1/3)²:2/9-1/6=
1/9 : 2/9 - 1/6 = mmc 18
2/18 : 4/18 - 3/18 =
2 : 4 - 3 /18 =
0,5 -3/18=
2,5/18
E)(3/8)*(4/5)²+(1/6)²=
3/8 . 16/25 + 1/36 =
48/200 + 1/36 =
12/50 + 1/36 = mmc 900
216/900 + 25/900 =
216 + 25/900 =
241 / 900 =
F) [(1/4)²+(1/2)³]=
1/16 + 1/8 = mmc 16
1/16 + 2/16 =
3/16
Perguntas interessantes
Filosofia,
9 meses atrás
Matemática,
9 meses atrás
Administração,
1 ano atrás
Biologia,
1 ano atrás
Matemática,
1 ano atrás