Question

resolva as expressões numéricas abaixo

a) 80+{5+[ (8+12)+(13+12)]+10}=

b) 58+[48-(31-10)+15]=

c) 38-{(51-15)+[5+(3-1)]-10}=

d) [9+(585-15x6)] /56=

e) [30-(17-8)x3+25]/7=

f) 3-2x[3+(4-5)x3]=

Answer 1

A = 80+{5+[(8+12)+(13+12)]+10}
80 + { 5 + [20 +25] + 10 }
80 + { 5 + 45 + 10 }
80 + 60
140

B = 58 + [48 - (31 - 10) + 15]
58 + [48 - 21 + 15]
58 + [27 + 15]
58 + 42
100

C = 38-{36+[5+2]-10} =
38-{36+7-10}=
38-33 = 5

D = [9+(585-90)]/56=
[9+495]/56=
504/56=
9

E = [30-(17-8).3+25]:7
[30 - (9).3 + 25 ]:7
[30 - 27 + 25 ]:7
28 : 7 = 4