Question

Resolva as Expressoes numerica
me ajufrm pfv

Answer 1

A) x² + 3x ; x = 10

10² + 3.10 = 100 + 30
= 130

B) 3a + 2b ; a = 6 e b = - 2

3.6 + 2.(-2) = 18 - 4
= 14

C) 6m - 4 n + 2 ; onde m = 3, n = 3

6.3 - 4.3 + 2 = 18 - 12 + 2
= 8

D) 4x² + 3x + 1 ; x = 5

4.5² + 3.5 + 1 = 4.25 + 15 + 1 = 100 + 15 + 1
= 116

E) v² + 2.∆S + T ; onde v = 3, ∆S = 10 e T = 2

3² + 2.10 + 2 = 9 + 20 + 2
= 31