Question

Resolva as expressoes a seguuir:

a (243) ^ 1/5
b) 3√27 + √36 + 3√8

resolvas as equações em R (real)
a) 128 ^x = 256
b) 64 ^x = 1/4

Answer 1

a (243) ^ 1/5 ==>  (3^5)^1/5 ==> 3^5/5 ==> 3^1 ==> 3
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b) 3√27 + √36 + 3√8 ==> 3√3².3 + 6 + 3√2².2

3.3√3 + 6 + 3.2√2 ==> 9√3 + 6√2 + 6

resolvas as equações em R (real)

a) 128 ^x = 256 ==> (2^7)^x = 2^8 ==> 7x = 8 ==> x = 8/7

b) 64 ^x = 1/4 ==> (4^3)^x = 4^-1 ==> 4^3x = 4^-1 ==> 3x= - 1 ==> x = - 1/4