Resolva as expressões
Soluções para a tarefa
16-10+(8+5)
16-10+3
9
C) 30-(2+1)²+2³
30-3²+8
30-9+8
29
D) 20-[6-4(10-3²)+1]
20-[6-4(10-9)+1]
20-(6-4.1+1)
20-(6-4+1)
20-3
17
E) 25+{3³/9+[3².5-3(2³-5)]}
25+{3³/3²+[3².5-3(8-5)]}
25+[3+(3².5-3.3)]
25+{3+[3.3(5-1)]}
25+[3+(3.3.4)]
25+(3+36)
25+39
64
F) (8/2).4+{[(3²-2³).2^4-5^0]4¹}
4.4+{[(9-8)2^4-1].4}
16+[(1.2^4-1).4]
16+[(2^4-1).4]
16+[(16-1).4]
16+(15.4)
16+60
76
b) 9
4² – 10 + (2³ – 5) =
4² – 10 + (8 – 5) =
4² – 10 + 3 =
16 – 10 + 3 =
6 + 3 =
9
c) 29
30 – (2 + 1)² + 2³ =
30 – 3² + 2³ =
30 – 9 + 2³ =
30 – 9 + 8 =
21 + 8 =
29
d) 17
20 – [6 – 4 × (10 – 3²) + 1] =
20 – [6 – 4 × (10 – 9) + 1] =
20 – [6 – 4 × 1 + 1] =
20 – [6 – 4 + 1] =
20 – [2 + 1] =
20 – 3 =
17
e) 62
25 + {3³ ÷ 9 + [3² × 5 − 3 × (2³ − 5)]} =
25 + {3³ ÷ 9 + [3² × 5 − 3 × (8 − 5)]} =
25 + {3³ ÷ 9 + [3² × 5 − 3 × 3]} =
25 + {3³ ÷ 9 + [9 × 5 − 3 × 3]} =
25 + {3³ ÷ 9 + [45 − 3 × 3]} =
25 + {3³ ÷ 9 + [45 − 9]} =
25 + {3³ ÷ 9 + 36} =
25 + {9 ÷ 9 + 36} =
25 + {1 + 36} =
25 + 37 =
62
f) 76
(8 ÷ 2) × 4 + {[(3² − 2³) × 2⁴ − 5⁰] × 4¹} =
(8 ÷ 2) × 4 + {[(9 − 2³) × 2⁴ − 5⁰] × 4¹} =
(8 ÷ 2) × 4 + {[(9 − 8) × 2⁴ − 5⁰] × 4¹} =
4 × 4 + {[(9 − 8) × 2⁴ − 5⁰] × 4¹} =
4 × 4 + {[1 × 2⁴ − 5⁰] × 4¹} =
4 × 4 + {[1 × 16 − 5⁰] × 4¹} =
4 × 4 + {[1 × 16 − 1] × 4¹} =
4 × 4 + {[16 − 1] × 4¹} =
4 × 4 + {15 × 4¹} =
4 × 4 + {15 × 4} =
4 × 4 + 60 =
16 + 60 =
76
Espero ter ajudado!
Bons estudos!