Question

resolva as expressão numerica 2×{18+[-3-(32÷(+4)-6)]}-(+10)​

Answer 1

Resposta:

$2\times\{18+[-3-(32)\div(+4)-6]\}-(+10)=\\ \\ 2\times\{18+[-3-(+8)-6]\}-10=\\ \\ 2\times\{18+[-3-8-6]\}-10=\\ \\ 2\times\{18+[-17]\}-10=\\ \\ 2\times\{18-17\}-10=\\ \\ 2\times(+1)-10\\ \\ 2-10=-8$