Question

Resolva as equacoes quadratica usando formula de bhaskara
-x²-15x-54=0​

Answer 1

Resposta:

Explicação passo-a-passo:

$-x^{2} -15x-54=0\\delta=b^{2} -4ac\\delta=(-15)^{2} -4.(-1).(-54)\\delta=225-216\\delta=9\\\\x'=\frac{-b+\sqrt{delta} }{2a} \\x'=\frac{15+\sqrt{9} }{-2} \\x'=\frac{15+3}{-2} \\x'=\frac{18}{-2} \\x'=-9\\\\x"=\frac{-b-\sqrt{delta} }{2a} \\x"=\frac{15-\sqrt{9} }{-2} \\x"=\frac{15-3}{-2} \\x"=\frac{12}{-2} \\x"=-6$

S = { -9, -6 }

Espero ter ajudado!