Question

Resolva as equações passo a passo:
$\frac{(4x-1)^{2}}{16} - x^{2} = 0$

Answer 1

$\frac{(4x-1)^2}{16}-x^2=0\\ \\ (4x-1)^2-16x^2=0\\ \\ 16x^2-8x+1-16x^2=0\\ \\ -8x+1=0\\ \\ x=\frac{1}{8}$