Question

Resolva as equações:
p) x²-5x+6=0
q)x²-7x+10=0
r)x²+x=0

Answer 1

p) x^2-5x+6=0
delta=b^2-4.a.c
delta=(-5)^2-4.1.6
delta=25-24
delta=1
x=-b-/+ raiz de delta/2a
x=-(-5)-1/2.1
x=5-1/2
x=4/2
x=2
x=-(-5)+1/2.1
x=5+1/2
x=6/2
x=3
q) x^2-7x+10=0
delta=b^2-4.a.c
delta=(-7)^2-4.1.10
delta=49-40
delta=9
x=-b-/+ raiz de delta/2a
x=-(-7)-3/2.1
x=7-3/2
x=4/2
x=2
x=-(-7)+3/2.1
x=7+3/2
x=10/2
x=5