Question

resolva as equações numéricas:
B)(5²-3.4) .2 + (3².2³+3) :5² -10:5=?
C)(5²-3.7) +(√49+3.2) 2-2³

Answer 1

B)(5²-3×4)×2+(3²×2³+3)÷5²-10÷5 =
   (25-12)×2+(9×8+3)÷25-10÷5 =
    13×2+(72+3)÷25-2 =
      26+75÷25-2 =
       26+3-2 = 
         29-2 =
           27
C)(5²-3×7)+(√49+3×2)2-2³ =
    (25-21)+(7+6)×2-8 =
      4+13×2-8 =
       4+26-8 =
        30-8 =
         22

Answer 2

b. (5²-3.4).2+(3².2³+3):5²-10:5
(25-12).2+(9.8+3):5²-10:5
13.2+(72+3):5²-10:5
13.2+75:5²-10:5
26+75:25-10:5
26+3-2
29-2
27

Espero ter ajudado!