Question

Resolva as equações modulares:
a) (x - 2) = 4
b) (x - 6) = 10
c) (x + 8) = 12
d) (x² - 5 . x + 6) = 2
e) (x² - 8 . x + 13) = 1

Answer 1

Explicação passo-a-passo:

a)(x-2)=4

x=4+2

x=6

b)(x-6)=10

x=10+6

x=16

c)(x+8)=12

x=12-8

x=4

d)(x2-5.x+6)=12

x2-5x+6-12=0 * lembrando que esse

x2-5x-6=0 x2 quer dizer x ao

a=1 quadrado*.

b=-5

c=-6 ∆=b2-4.a.c

∆=(-5)2-4.1.(-6)

∆=25-4.(-6)

∆=25+24

∆=49

X=-(-5)+√49

___-____

2.1

x=5+7

__-__

2

x'=5+7 x"=5-7

____ ___

2 2

x'=12

___ x"=-2

2 ___

2

x'=6 x"=-1

S={-1,6}

e)x2-8x+13-1=0

x2-8x+12=0

a=1

b=-8

c=12

∆=(-8)2-4 1.12

∆=64-48

∆=16

x=-(-8)+ ou -√16

____________

2.1

x=8+ou -4

_________

2

x'=8+4

_____

2

x'=12/2

x'=6

x"=8-4

___

2

x"=4/2

x"2

S={2,6}