Question

Resolva as equações
i) 3(x+1)+2(2x-3)=5 (x-1)+8
j) 2(x+5)-4=26
K) 3(x+3)-5=22

Answer 1

$\sf3(x+1)+2(2x-3)=5(x-1)+8$

$\sf3x+3+4x-6=5x-5+8$

$\sf7x-3=5x+3$

$\sf7x-5x=3+3$

$\sf2x=6$

$\sf x=\dfrac{6}{2}$

$\boxed{\boxed{\sf x=3}}$

$\sf2(x+5)-4=26$

$\sf2x+10-4=26$

$\sf2x+6=26$

$\sf2x=26-6$

$\sf2x=20$

$\sf x=\dfrac{20}{2}$

$\boxed{\boxed{\sf x=10}}$

$\sf3(x+3)-5=22$

$\sf3x+9-5=22$

$\sf3x+4=22$

$\sf3x=22-4$

$\sf3x=18$

$\sf x=\dfrac{18}{3}$

$\boxed{\boxed{\sf x=6}}$