Question

resolva as equações exponenciais na incógnita X: A) (0,01)^x-1=1000 B) (4^x)^x=512^2 C) (0,25)^x-1=(1\8)^1-x

Answer 1

A) (0,01)^x-1 = 1000
(10^-2)^x-1= 10³
10^-2x+2= 10³
-2x+2=3
-2x=3-2
x=-1/2

b)(4^x)^x= 512^2
4x² = 2^9^2
2²^x² = 2^18
2^2x²=2^18
2x²=18
x²=9
x=3

C) (0,25)^x-1= (1/8)^1-x
(25/100)^x-1=8^-1+x
(1/4)^x-1 = 8^-1+x
4^-x+1=8^-1+x
2^-2x+2= 2^-3+3x
-2x+2=-3+3x
3x-2x=2+3
x=5