resolva as equações exponenciais . ajudem!
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23) 4x^2/4+4x/4=4^12/4
x^2+x=4^11
x^2+x-4^11
b^2-4ac=1^2-4x1x4^11= 1+4^12
-b±√∆/2a=-1±√1+4^12
x'=-1-√√1+4^12
x''=-1+√1+4^12.
24) 2^x^2-x=2^2
anule as duas bases (2)
x^2-x=2
x^2-x-2=0
b^2-4ac= (-1)^2-4x1x(-2)= 1+8=9
-b±√∆/2a=1±√9/2x1=1±3/2
x''= 1+3/2=4/2=2
x'=1-3/2=-2/2=-1.
25) (2^x)^x+4=32
2x^2+4x=2^5
anule as bases (2)
x^2+4x=5
x^2+4x-5=0
b^2-4ac=4^2-4x1x(-5)= 16+20=36
-b±√∆/2a= 4±√36/2x1=4±6/2
x''=-4+6/2=-2/2=1
x'1=-4-6/2=-10/2=-5
x^2+x=4^11
x^2+x-4^11
b^2-4ac=1^2-4x1x4^11= 1+4^12
-b±√∆/2a=-1±√1+4^12
x'=-1-√√1+4^12
x''=-1+√1+4^12.
24) 2^x^2-x=2^2
anule as duas bases (2)
x^2-x=2
x^2-x-2=0
b^2-4ac= (-1)^2-4x1x(-2)= 1+8=9
-b±√∆/2a=1±√9/2x1=1±3/2
x''= 1+3/2=4/2=2
x'=1-3/2=-2/2=-1.
25) (2^x)^x+4=32
2x^2+4x=2^5
anule as bases (2)
x^2+4x=5
x^2+4x-5=0
b^2-4ac=4^2-4x1x(-5)= 16+20=36
-b±√∆/2a= 4±√36/2x1=4±6/2
x''=-4+6/2=-2/2=1
x'1=-4-6/2=-10/2=-5
guilhermekairo:
cade a 25?
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