Question

Resolva as equações exponenciais : (3^x)^x-4 = 1 / 27 ? >> / : (1 sobre 27) ^ : ( elevado ) 

Answer 1

(3^x)^x-4 = 1 / 27

(3^x)^x-4 = 3^-3
 x(x-4) = - 3
x² - 4x + 3 = 0

Δ= 4

x1= 3   e x2 = 1

Answer 2

$(3^x)^{x-4}=\frac{1}{27}\\\\3^{x(x-4)}=\frac{1}{3^3}\\\\3^{x^2-4x}=3^{-3}\\\\x^2-4x=-3\\\\x^2-4x+3=0\\\\(x-1)(x-3)=0\\\\\boxed{x=1}\\\boxed{x=3}$