Question

resolva as equações exponenciais:

Answer 1

Resposta:

A) 2 × 3^(x - 2) = 486

3^(x - 2) = 243

3^(x - 2) = 3^5

x - 2 = 5

x = 5 + 2

x = 7

B) 3^2x + 3^(x + 1) = 18

(3^x)² + 3^x × 3 = 18

t² + t × 3 = 18

t² + 3t - 18 = 0

∆ = 9 + 72

∆ = 81

t" = 3

3^x = 3

x = 1

C) (0,4)^(4x + 1) = ³√(5/2)

(2/5)^(4x + 1) = (2/5)^(-1/3)

4x + 1 = -⅓

4x = -⅓ - 1

4x = -4/3

x = -1/3

D) 4^x - 4^(x - 1) = 24

(4 - 1) × 4^(x - 1) = 24

3 × 4^(x - 1) = 24

4^(x - 1) = 8

2^(2x - 2) = 2³

2x - 2 = 3

2x = 5

x = 5/2

Espero Ter Ajudado !!