Question

Resolva as equacoes em R:
A.(x+3)^2=1
B. (3x+1)^2=0
C. (2x-4)^2=0
D. (X-3)^2=0
E. x.(x-3)^2=2x^2
F. X.(x-5)=-6
G. X^2
-------- + x=0
2
H. (X+5). (X+5)=0
I. X^2+3x=2
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6 3
J.5x^2 - 2x=0
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3 5

Answer 1

a) 2.(3x - 1) + 2.(3 - x)= 0
6x - 2 + 6 - 2x= 0
6x - 2x = + 2- 6
4x = - 4
x = - 4/4
x = -1
b) 7.( x- 1)  = 2.( 3x + 1)
7x - 7 = 6x + 2
7x - 6x = 2 + 7
x = 9
c) 2.( 3 - y) + 7(2 - y) = 15 - 4y
6 - 2y  + 14 - 7y = 15 - 4y
- 2y - 7y + 4y = 15 - 6 - 14
- 5y = - 5( multiplicando por -1)
5y = 5
y = 5/5
y= 1
d) 2( x - 2) + 5 ( 2x - 2) + 6( x + 1 ) = 0
2x - 4 + 10x - 10 + 6x + 6 = 0
2x + 10x + 6x = 4 + 10 - 6
18x = 8
x = 8/18
x = 4/9
e) 3 ( x - 2) - ( 1 - x) = 13
3x - 6 -1 + x = 13
3x + x= 13 + 6 + 1
4x = 20
x = 20/4
x = 5
f) x - ( x + 1) = 12 - ( 3x - 2)
x - x - 1 = 12 - 3x + 2
x - x + 3x = 12 + 2 + 1
3x = 15
x = 15/3
5
g) x/2 = 12/3
MMC de 2 e 3 = 6
x/2/3 = 12/3/2
3x = 24
x = 24/3
x = 8
h) 2x/3 + 1/2 = x/4 - 3/2
MMC de 3 e 2 = 6
2x/3/2 + 1/2/3 = x/4/3 - 3/2/3
4x + 3 = 3x - 9
4x - 3 x = - 9 - 3
x = - 12
i) x/3 - 1 + 3/4 = x/2 - 1/4
MMC de 3, 4 e 2 = 12
x/3/4 - 1/1/12 = x/2/6 - 1/4/3
4x - 12 = 6x - 3
4x - 6x = - 3 + 12
- 2x = 9(multiplicndo por - 1)
2x = - 9
x = - 9/2