Question

Resolva as equações em Q. (2x-3). (5x+2)=0

Answer 1

Resolva as equações em Q.
 
(2x-3). (5x+2)=0
 10x² + 4x - 15x - 6 = 0
 10x² - 11x - 6 = 0

Δ = b²-4ac = 121 + 240= 361
√Δ = +-√361 = +-19

x1 = (11+19)/20 = 30/20 = 3/2
x2=  (11-19)/20 = -8/20 = - 2/5

S = {-2/5 , 3/2}

Answer 2

(2x-3).(5x+2)=0
2x(5x+2)+  -3(5x+2)=0
10x² + 4x -15x - 6 =0
10x² - 11x -6 
Δ= (-11)² - 4.10.-6
Δ= 121 + 240
Δ= 361
X= -(-11) +/- √Δ ÷ 2.10
X= 11+/-√361 ÷ 2.10
X= 11+/-19 ÷ 20
x1= 11+19 ÷ 20 =30 ÷ 20 = $\frac{3}{2}$
x2= 11-19 ÷ 20 = -8 ÷ 20 = $\frac{-2}{5}$