Question

Resolva as equações eliminando os denominadores 
x/2 + x-4/5 = x-3/2
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x + x/2 = 12
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x/4 - 1 = 2 + x/10

Obs: / é igual a Sobre ( x sobre 2...)

Answer 1

veja

$\frac{x}{2} +x- \frac{4}{5} =x- \frac{3}{2}$

mmc=10

$\frac{5x+10x-8=10x-15}{10}$

$5x+10x-10x=-15+8$

$5x=-7 \\ x=- \frac{7}{5}$

b)
$x+ \frac{x}{2} =12$

mmc=2

$\frac{2x+x=24}{2} \\ 3x=24 \\ x=24\div3 \\ x=8$

c)
$\frac{x}{4} -1=2+ \frac{x}{10}$

mmc=20

$\frac{5x-20=40+2x}{20} \\ 5x-2x=40+20 \\ 3x=60 \\ x=60\div3 \\ x=20$

d)
$\frac{x}{4} +2=x- \frac{3}{2}$

mmc=4

$\frac{x+8=4x-6}{4} \\ x-4x=-6-8 \\ -3x=-14 \\ 3x=14 \\ x= \frac{14}{3}$

Answer 2

a) $\dfrac{x}{2}+\dfrac{x-4}{5}=\dfrac{x-3}{2}$

$\dfrac{5x+2(x-4)}{10}=\dfrac{5(x-3)}{10}$

$5x+2x-8=5x-15$

$2x=8-15$

$2x=-7$

$x=-\dfrac{7}{2}$


a) $\dfrac{x}{2}+x-\dfrac{4}{5}=x-\dfrac{3}{2}$

$\dfrac{5x+10x-8}{10}=\dfrac{10x-15}{10}$

$15x-8=10x-15$

$5x=-7$

$x=-\dfrac{7}{5}$


b) $x+\dfrac{x}{2}=12$

$2x+x=24$

$3x=24$

$x=8$

c) $\dfrac{x}{4}-1=\dfrac{2+x}{10}$

$\dfrac{5x-20}{20}=\dfrac{2(2+x)}{20}$

$5x-20=4+2x$

$3x=24$

$x=8$

c) $\dfrac{x}{4}-1=2+\dfrac{x}{10}$

$\dfrac{5x-20}{20}=\dfrac{40+2x}{20}$

$5x-20=40+2x$

$3x=60$

$x=20$