Question

resolva as equações
e) 18x-43=65
f) 23x-16=14-17x
g) 10y-5(1+y)=3(2y-2)-20
h) x(x+4)+x(x+2)=2x^2+12
i) 3(2x-3)+2(x+1)=3x+18
j)2x+3(x-5)=4x+9
k)2(x+1)-3(2x-5)=6x-3
l) 3x-5=x-2

Answer 1

E) 18x - 43 = 65
18x = 65 + 43
18x = 108
x = $\frac{108}{18}$
x = 6

F) 23x - 16 = 14 - 17x
23x + 17x = 14 + 16
40x = 30
x = $\frac{30}{40}$ 
x = $\frac{3}{4}$

G) 10y - 5(1+y) = 3(2y-2) - 20
10y - 5 - 5y = 6y - 6 -20
5y - 5 = 6y - 26
5y - 6y = -26 + 5
-y = -21 .(-1)
x = 21 

H) x(x+4) + x(x+2) = 2$x^{2}$ + 12
$x^{2}$ + 4x + $x^{2}$ + 2x = 2$x^{2}$ + 12
2$x^{2}$ + 6x - 2$x^{2}$ = 12
6x = 12
x  = $\frac{12}{6}$
x = 2

I) 3 (2x - 3) + 2 (x+1) = 3x + 18
6x - 9 + 2x + 2 = 3x + 18
8x - 3x = 18 - 2 + 9
5x = 25
x = $\frac{25}{5}$
x = 5

J) 2x + 3 (x - 5) = 4x + 9
2x + 3x - 15 = 4x + 9
5x - 4x = 9 + 15
x = 24

K) 2 (x+1) - 3 (2x - 5) = 6x - 3
2x + 2 - 6x + 15 = 6x - 3
2x - 6x - 6x = -3 - 2 - 15
-10x = -20 .(-1)
x = $\frac{20}{10}$
x = 2

L) 3x - 5 = x - 2
3x - x = -2 + 5
2x = 3
x = $\frac{3}{2}$

Answer 2

e a 18 gente vcs entenderao