Question

RESOLVA AS EQUAÇÕES DO 2º GRAU ONDE B= 0.

$x^{2}-100=0$

$9 x^{2}-81=0$

$2 x^{2}=200$

$x^{2}-2=0$

$x^{2}-121=0$

$x^{2}=16$

$4 x^{2}=100$

$x^{2}=16$

Answer 1

$x^{2}-100=0 \\\\ x^{2}=100 \\\\ x = \pm \sqrt{100} \\\\ \boxed{x = \pm 10}$


$9x^{2}-81=0 \\\\ 9x^{2} = 81 \\\\ x^{2} = \frac{81}{9} \\\\ x^{2} = 9 \\\\ x = \pm \sqrt{9} \\\\ \boxed{x = \pm 3}$


$2x^{2} = 200 \\\\ x^{2} = \frac{200}{2} \\\\ x^{2} = 100 \\\\ x = \pm \sqrt{100} \\\\ \boxed{x = \pm 10}$


$x^{2}-2=0 \\\\ x^{2} = 2 \\\\\ \boxed{x = \pm \sqrt{2}}$


$x^{2}-121=0 \\\\ x^{2} = 121 \\\\ x = \pm \sqrt{121} \\\\ \boxed{x = \pm 11}$


$x^{2} = 16 \\\\ x = \pm \sqrt{16} \\\\ \boxed{x = \pm 4}$


$4x^{2} = 100 \\\\ x^{2} = \frac{100}{4} \\\\ x^{2} = 25 \\\\ x = \pm \sqrt{25} \\\\ \boxed{x = \pm 5}$


Quando o B vale zero, só temos que trabalhar com operações simples.

Answer 2

x²-100=0
x²=100
x=√100
x=+-10

9x²-81=0
9x²=81
x²=81/9
x²=9
x=√9
x=+-3

2x²=200
x²=200/2
x²=100
x=√100
x=+-10


x²-2=0
x²=2
x=+-√2

x²-121=0
x²=121
x=√121
x=+-11


x²=16
x=√16
x=+-4

4x²=100
x²=100/4
x²=25
x=√25
x=+-5


x²=16
x=√16
x=+-4