Question

Resolva as equações do 2º grau completas:
A)X² +X-6=0
B) x2 - X-6 = 0
C) x2 + 2x - 3 = 0
D) x2 – 3x + 2 = 0​
é urgenteeee

Answer 1

Respostas explicadas passo-a-passo:

A) X² + X - 6 = 0

    Δ= $b^{2} -4.ac$

    Δ= $1^{2} -4.1.(-6)$

    Δ= $1+24$

    Δ= $25$

    X= $\frac{-b+-\sqrt{delta} }{2.a}$

    X= $\frac{-1+-\sqrt{25} }{2.1}$

    X= $\frac{-1+-5}{2}$

→  $X^{1} = \frac{-1-5}{2} =\frac{-6}{2} = -3$

→  $X^{2} = \frac{-1+5}{2} =\frac{4}{2} =2$

B) X² - X - 6 = 0

    Δ= $b^{2} -4.ac$

    Δ= $-1^{2} -4.1.(-6)$

    Δ= $1+24$

    Δ= $25$

    X= $\frac{-b+-\sqrt{delta} }{2.a}$

    X= $\frac{-1+-\sqrt{25} }{2.1}$

    X= $\frac{-1+-5}{2}$

→  $X^{1} = \frac{-1-5}{2} =\frac{-6}{2} = -3$

→  $X^{2} = \frac{-1+5}{2} =\frac{4}{2} =2$

C) X² + 2x - 3 = 0

    Δ= $b^{2} -4.ac$

    Δ= $2^{2} -4.1.(-3)$

    Δ= $4+12$

    Δ= $16$

    X= $\frac{-b+-\sqrt{delta} }{2.a}$

    X= $\frac{-2+-\sqrt{16} }{2.1}$

    X= $\frac{-2+-4}{2}$

→  $X^{1}= \frac{-2-4}{2} =\frac{-6}{2} =-3$

→  $X^{2} =\frac{-2+4}{2} =\frac{2}{2} =1$

D) X² – 3x + 2 = 0​

    Δ= $b^{2} -4.ac$

    Δ= $-3^{2} -4.1.2$

    Δ= $9-8$

    Δ= $1$

    X= $\frac{-b+-\sqrt{delta} }{2.a}$

    X= $\frac{-(-3)+-\sqrt{1} }{2.1}$

    X= $\frac{3+-1 }{2}$

→  $X^{1} =\frac{3+1}{2} =\frac{4}{2} =2$

→  $X^{2} =\frac{3-1}{2} =\frac{2}{2} =1$