Question

resolva as equações do 2°, usando a fórmula de bháskara:
a) x² - 7 x + 10 = 0
b) x² +5 x + 4 = 0
c) 2 x² - 4 x + 2 = 0
d) x ² - 5 x - 6 = 0
explique a resposta pfvr.​

Answer 1

$\boxed{\boxed{\bf{\red{Olá }}}}$

Vamos a os cálculos

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a) x² - 7 x + 10 = 0

A = 1 B = -7 C = 10

Δ = B² - 4.A.C

Δ = (-7)²- 4.1.10

Δ = 49 - 40

Δ = 9

X = -B +- √Δ / 2.A

X = -(-7) +- √9 / 2.1

X = 7 +- 3 / 2

X| = 7 + 3 / 2

X| = 10 / 2

X| = 5

X|| = 7 - 3 / 2

X|| = 4 / 2

X|| = 2

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b) x² +5 x + 4 = 0

A = 1 B = 5 C = 4

Δ = B² - 4.A.C

Δ = 5² - 4.1.4

Δ = 25 - 16

Δ = 9

X = -B +- √Δ / 2.A

X = -5 +- √9 / 2.1

X = -5 +- 3 / 2

X| = -5 + 3 / 2

X| = -2 / 2

X| = -1

X|| = -5 - 3 / 2

X|| = -8 / 2

X|| = -4

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c) 2 x² - 4 x + 2 = 0

A = 2 B = -4 C = 2

Δ = B² - 4.A.C

Δ = (-4)² - 4.2.2

Δ = 16 - 16

Δ = 0

X = -B +- √Δ / 2.A

X| = X|| = -4 / 4

X| = X|| = -1

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d) x ² - 5 x - 6 = 0

A = 1 B = -5 C = -6

Δ = B² - 4.A.C

Δ = (-5)² - 4.1.(-6)

Δ = 25 + 24

Δ = 49

X = -B +- √Δ / 2.A

X = -(-5) +- √49 / 2.1

X = 5 +- 7 / 2

X| = 5 + 7 / 2

X| = 12 / 2

X| = 6

X|| = 5 - 7 / 2

X|| = -2 / 2

X|| = -1