Question

resolva as equações dentro do conjunto-universo Q:

a) X+X/2=3
b) 3(y-5)+7y=5(3-y)
c) X/2-X/3=1
d)X/3+4=X/2+8
preciso de ajuda rapido​​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{x + \dfrac{x}{2} = 3}$

$\mathsf{\dfrac{2x + x}{2} = 3}$

$\mathsf{3x = 6}$

$\mathsf{x = \dfrac{6}{3}}$

$\boxed{\boxed{\mathsf{x = 2}}}\leftarrow\textsf{letra A}$

$\mathsf{3(y - 5) + 7y = 5(3 - y)}$

$\mathsf{3y - 15 + 7y = 15 - 5y}$

$\mathsf{15y = 30}$

$\mathsf{y = \dfrac{30}{15}}$

$\boxed{\boxed{\mathsf{y = 2}}}\leftarrow\textsf{letra B}$

$\mathsf{\dfrac{x}{2} - \dfrac{x}{3} = 1}$

$\mathsf{\dfrac{3x - 2x}{6} = 1}$

$\boxed{\boxed{\mathsf{x = 6}}}\leftarrow\textsf{letra C}$

$\mathsf{\dfrac{x}{3} + 4 = \dfrac{x}{2} + 8}$

$\mathsf{\dfrac{x + 12}{3} = \dfrac{x + 16}{2}}$

$\mathsf{2x + 24 = 3x + 48}$

$\mathsf{x = 24 - 48}$

$\boxed{\boxed{\mathsf{x = -24}}}\leftarrow\textsf{letra D}$

Answer 2

Vamos lá!

a)

$x + \frac{x}{2} = 3 \\ \frac{ 2x + x}{2} = \frac{6}{2} \\ 2x + x = 6 \\ 3x = 6 \\ x = \frac{6}{3} \\ \blue{ \boxed{ x = 2}}$

b)

$3(y - 5) + 7y = 5(3 - y) \\ 3y - 15 + 7y = 15 - 5y \\ 10y + 5y = 15 + 15 \\ 15y = 30 \\ y = \frac{30}{15} \\ \blue{\boxed{ y = 2}}$

c)

$\frac{x}{2} - \frac{x}{3} = 1 \\ \frac{3x - 2x}{6} = \frac{6}{6} \\3x - 2x = 6 \\ \blue{\boxed{x = 6}}$

d)

$\frac{x}{3} + 4 = \frac{x}{2} + 8 \\ \frac{2x + 24}{6} = \frac{3x + 48 }{6} \\ 2x + 24 = 3x + 48 \\ 2x - 3x = 48 - 24 \\ - x = 24 \times ( - 1) \\\blue{\boxed{ x = - 24}}$