Question

resolva as equações de 2°grau .. a) x2-5x+6=0 B) x2-8x+12=0

Answer 1

a)

x²-5x+6 = 0

b²-4ac = Δ

(-5)² - 4.1.6

25-24 = Δ

1 = Δ

-b+-√Δ/2a

-(-5)+-√1/2.1

(l) 5+1/2 = 6/2 = 3

(ll) 5-1/2 = 4/2 = 2

b) x² - 8x +12 = 0

b²-4ac = Δ

(-8)² - 4.1.12

64-48 = Δ

16 = Δ

-b+-√Δ/2a

-(-8)+-√16/2.1

(l) 8+4/2 = 12/2 = 6

(ll) 8-4/2 = 4/2 = 2