Question

Resolva as equações completas abaixo.
A) 3x²+10x-8=0
B) X²+6x+8=0

OBS: Com cálculo!​

Answer 1

⭕ Equação do segundo Grau!!

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Letra A)

Δ = b² - 4ac

Δ = (10²) -4*3*-8

Δ = 100-4*3*-8

Δ = 100-(-96)

Δ = 196

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X1 = -b + √ Δ/ 2*a

X1 = -(10) + √196/ 2*3

X1 = (-10) + 14.00/ 6

X1 = 4.00/ 6

X1 = 0.67

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X2 = -b - √ Δ/ 2*a

X2 = -(10) - √196/ 2*3

X2 = (-10) - 14.00/ 6

X2 = -24.00/ 6

X2 = -4

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Raízes: 0,67 e -4

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Letra B)

Δ = b² - 4ac

Δ = (6²) -4*1*8

Δ = 36-4*1*8

Δ = 36-(32)

Δ = 4

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X1 = -b + √ Δ/ 2*a

X1 = -(6) + √4/ 2*1

X1 = (-6) + 2.00/ 2

X1 = -4.00/ 2

X1 = -2

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X2 = -b - √ Δ/ 2*a

X2 = -(6) - √4/ 2*1

X2 = (-6) - 2.00/ 2

X2 = -8.00/ 2

X2 = -4

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Raízes: -2 e -4

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$\huge \boxed{Bons \: \: estudos }$

Answer 2

Explicação passo-a-passo:

A) 3x^2+10-8=0

a=3 delta=10^2-4.3.(-8)

b=10 delta=100-12.(-8)

c=-8 delta=100+96 = 196

x'= -10+14/6= 4/6

x"= -10-14/6= 24/6=4

B)x^2+6x+8=0

a=1 delta=6^2-4.1.8

b=6 delta=36-32=4

c=8

x'= -6+2/2= -4/2= -2

x"= -6-2/2= -8/2= -4