Question

resolva as equações abaixo: E) X ²+ 3x=10

Answer 1

${x}^{2} + 3x = 10 \\ {{x}^{2} + 3x} - 10 = 0 \\ delta = {b}^{2} - 4ac \\ delta = {3}^{2} - 4(1)( - 10) \\ delta = 9 + 40 \\ delta = 49 \\ x = \frac{ - b + - \sqrt{delta} }{2a} \\ x1 = \frac{ - 3 + 7}{2} = \frac{4}{2} \\ x1 = 2 \\ x2 = \frac{ - 3 - 7}{2} = \frac{ - 10}{2} \\ x2 = - 5$

X={2; -5}