Question

Resolva as equações abaixo e ache o valor delta:

1- X^2-5x+2=0

2- X^2+x-20=0

3- X^2-3x-18=0

4- 2x^2+4x+2=0

5- X^2-12x+20=0

6- 3x^2-48=0

Alguém pode me ajudar?!

Answer 1

Resposta:

Explicação passo-a-passo:

1-)  

a=1

b=−5

c=2

x=−(−5)±(−5)2−4×(1)×(2)−−−−−−−−−−−−−−−−−−√2×(1)⇔

x=5±25−(8)−−−−−−−√2⇔

x=5±17−−√2⇔

x=5+4.12312∨x=5−4.12312⇔

x=9.12312∨x=0.87692

S={4.5616,0.4385}

2-

2x2+1x−20=0

a=2

b=1

c=−20

x=−(1)±(1)2−4×(2)×(−20)−−−−−−−−−−−−−−−−−−−√2×(2)⇔

x=−1±1−(−160)−−−−−−−−−−√4⇔

x=−1±161−−−√4⇔

x=−1+12.68864∨x=−1−12.68864⇔

x=11.68864∨x=−13.68864

S={2.9222,−3.4222}

3-

x2−3x−18=0

a=1

b=−3

c=−18

x=−(−3)±(−3)2−4×(1)×(−18)−−−−−−−−−−−−−−−−−−−−−√2×(1)⇔

x=3±9−(−72)−−−−−−−−−√2⇔

x=3±81−−√2⇔

x=3+92∨x=3−92⇔

x=122∨x=−62

S={6,−3}

4-

2x2+4x+2=0

a=2

b=4

c=2

x=−(4)±(4)2−4×(2)×(2)−−−−−−−−−−−−−−−−√2×(2)⇔

x=−4±16−(16)−−−−−−−−√4⇔

x=−4±0–√4⇔

x=−4+04⇔

x=−44

S={−1}

5-

x2−12x+20=0

a=1

b=−12

c=20

x=−(−12)±(−12)2−4×(1)×(20)−−−−−−−−−−−−−−−−−−−−√2×(1)⇔

x=12±144−(80)−−−−−−−−−√2⇔

x=12±64−−√2⇔

x=12+82∨x=12−82⇔

x=202∨x=42

S={10,2}

6-

3x^2-48=0

x^2=48/3

x^2=16

x= raiz 16

x= 4