resolva as equaçoes :
a) x/3 +x/2 =15
b) x-1)/4-(x-3)/6=3
Soluções para a tarefa
Respondido por
85
a)
![\frac{x}{3}+\frac{x}{2}=15 \\
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2x+3x=90 \\
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5x=90 \\
\\
x=\frac{90}{5}=18 \frac{x}{3}+\frac{x}{2}=15 \\
\\
2x+3x=90 \\
\\
5x=90 \\
\\
x=\frac{90}{5}=18](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D%2B%5Cfrac%7Bx%7D%7B2%7D%3D15++%5C%5C%0A%5C%5C%0A2x%2B3x%3D90++%5C%5C%0A%5C%5C%0A5x%3D90++%5C%5C%0A%5C%5C%0Ax%3D%5Cfrac%7B90%7D%7B5%7D%3D18)
b)
![\frac{x-1}{4}-\frac{x-3}{6}=3 \\
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3(x-1)-2(x-3)=36 \\
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3x-3-2x+6=36 \\
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3x-2x=36+3-6 \\
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x=33 \frac{x-1}{4}-\frac{x-3}{6}=3 \\
\\
3(x-1)-2(x-3)=36 \\
\\
3x-3-2x+6=36 \\
\\
3x-2x=36+3-6 \\
\\
x=33](https://tex.z-dn.net/?f=%5Cfrac%7Bx-1%7D%7B4%7D-%5Cfrac%7Bx-3%7D%7B6%7D%3D3++%5C%5C%0A%5C%5C%0A3%28x-1%29-2%28x-3%29%3D36++%5C%5C%0A%5C%5C%0A3x-3-2x%2B6%3D36++%5C%5C%0A%5C%5C%0A3x-2x%3D36%2B3-6++%5C%5C%0A%5C%5C%0Ax%3D33)
b)
Respondido por
47
x + x = 15
3 2 m.m.c
2x+3x=15
6
2x+3x=6.15
5x=90
x=90/5
x=18
B)
x-1 - x-3=3
4 6
3(x-1)-2(x-3)=12.3
3x-3-2x+6=36
3x-2x=36+3-6
1x=33
x=33/1
x=33
Espero te ajudado
3 2 m.m.c
2x+3x=15
6
2x+3x=6.15
5x=90
x=90/5
x=18
B)
x-1 - x-3=3
4 6
3(x-1)-2(x-3)=12.3
3x-3-2x+6=36
3x-2x=36+3-6
1x=33
x=33/1
x=33
Espero te ajudado
AntoniLAD:
Editei a resposta :)
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