Question

resolva às equações

a)x'2+4×-12=0

b) ×'2+6×-7=0

c) x'2+12×+32=0

d) x'2+2×+1=0

​

Answer 1

a) x²+4x-12

∆= b²-4ac

∆= 4²-4*1*(-12)

∆= 16+48

∆= 64

x½= -b±√∆/2a

x½= -4±√64/2*1

x1= -4+8/2

x1= 2

x2= -4-8/2

x2= -6

b)x²+6x-7=0

∆=b²-4ac

∆= 6²-4*1*(-7)

∆= 36+28

∆= 64

x½= -b±√∆/2a

x½= -6±√64/2*1

x½= -6±8/2

x1= -6+8/2=

x2= -6-8/2

x2= -7

c) x²+12x+32=0

∆=b²-4ac

∆= 12²-4*1*32

∆=144-128

∆= 16

x⅓= -b±√∆/2a

x½= -12±√16/2*1

x1= -12+4/2

x1= -4

x2= -12-4/2

x2= -8

d) x²+2x+1=0

∆=b²-4ac

∆= 2²-4*1*1

∆= 0

x½= -b±√∆/2a

x½= -2+√0/2*1

x1= -2+0/2

x1= -1

x2= -2-0/2

x2= -1

espero ter ajudado!!!