Question

Resolva as equações a seguir:
a) x²+2x-8=0, para a=1, b=2, c= -8
b) x²-14x + 49=0, para a=1, b= -14, c=49

Answer 1

$x^{2} +2x-8=0 \Delta= b^{2} -4.a.c \Delta= 2^{2} -4.1.(-8) \Delta=4+32=36 [tex]x1=-+ 2\sqrt{36} /2=-2+6/2=4/2=2 x2=-+2 \sqrt{36}/2=-2-6/2=-8/2=-4$


$x^{2} -14x+49=0 \Delta= b^{2} -4.a.c \Delta= -14^{2} -4.1.49 \Delta=196-196=0$
$x1=-+(-14) \sqrt{0} /2=14-0/2=7 x2=-+(-14) \sqrt{0} /2=14+0/2=7$