Question

Resolva as equações:

a) a/4 - 5/3 = 1/12

b) x/5 + 3 = -1

c) y-2= 3/2

d) 2z + 3 = z + 2/3

e) x+ 5/2= 8+2/5x

f) 7×-2×-3/4=3(x-8)

g) 5x/4 -3 - 3x/2 + 8 = 6x/3 - 3 + x/2

h) x/8 + 3 = 5/4

i) 3/2 x + 2 = 3/2 + x

j) x/2 - 5 = x + 3/4

k) x/2 + 1/3 = 4

Por favor me ajudem!
Agradecida!

Answer 1

$a)\\ \\ \frac{a}{4} -\frac{5}{3} =\frac{1}{12} \\ \\ mmc=12\\ \\ \frac{3a-20=1}{12} \\ \\ 3a-20=1\\ \\ 3a=1+20\\ \\ 3a=21\\ \\ a=\frac{21}{3} \\ \\ a=7\\ \\ b)\\ \\ \frac{x}{5} +3=-1\\ \\ \frac{x}{5} =-1-3\\ \\ \frac{x}{5} =-4\\ \\ x=5.(-4)\\ \\ x=-20\\ \\ c)\\ \\ y-2=\frac{3}{2} \\ \\ y=\frac{3}{2} +2\\ \\ mmc=2\\ \\ y=\frac{3+4}{2} \\ \\ y=\frac{7}{2}$

$d)\\ \\ 2z+3=z+\frac{2}{3} \\ \\ 2z-z=\frac{2}{3} -3\\ \\ z=\frac{2-9}{3} \\ \\ z=-\frac{7}{3} \\ \\ e)\\ \\ x+\frac{5}{2} =8+\frac{2}{5x} \\ \\ x-\frac{2}{5x} =8-\frac{5}{2} \\ \\ mmc=10x\\ \\ \frac{10x^{2}-4=80x-25x}{10x} \\ \\ 10x^{2} -80x+25x-4=0\\ \\ 10x^{2} -55x-4=0\\ \\ f)\\ \\ 7x-2x-\frac{3}{4} =3.(x-8)\\ \\ 7x-2x-\frac{3}{4} =3x-24\\ \\ 7x-2x-3x=-24+\frac{3}{4} \\ \\ 2x=-24+\frac{3}{4} \\ \\ mmc=4\\ \\ \frac{8x=-96+3}{4} \\ \\ 8x=-93\\ \\ x=-\frac{93}{8}$

$g)\\ \\ \frac{5x}{4} -3-\frac{3x}{2} +8=\frac{6x}{3} -3+\frac{x}{2} \\ \\ mmc=12\\ \\ \frac{15x-36-18x+96=24x-36+6x}{12} \\ \\ 15x-18x-24x-6x=-36+36-96\\ \\ -33x=-96\\ \\ 33x=96\\ \\ x=\frac{96}{33} \\ \\ x=\frac{32}{11}$

$h)\\ \\ \frac{x}{8} +3=\frac{5}{4} \\ \\ mmc=8\\ \\ \frac{x+24=10}{8} \\ \\ x=10-24\\ \\ x=-14\\ \\ i)\\ \\ \frac{3}{2x} +2=\frac{3}{2} +x\\ \\ mmc=4x\\ \\ \frac{6+8x=6x+4x^{2}}{4x} \\ \\ 4x^{2} +6x-8x-6=0\\ \\ 4x^{2} -2x-6=0\\ \\ j)\\ \\ \frac{x}{2} -5=x+\frac{3}{4} \\ \\ mmc=4\\ \\ \frac{2x-20=4x+3}{4} \\ \\ 4x-2x=-20-3\\ \\ 2x=-23\\ \\ x=-\frac{23}{2}$

$k)\\ \\ \frac{x}{2} +\frac{1}{3} =4\\ \\ mmc=6\\ \\ \frac{3x+2=24}{6} \\ \\ 3x=24-2\\ \\ 3x=22\\ \\ x=\frac{22}{3}$