Matemática, perguntado por moanadias945, 3 meses atrás

Resolva as equações

A) 7 (X - 5) = 3 (X + 1)
B) 3 (X - 2 ) = 4 ( - X + 3 )
C) 2 ( X + 1 ) - ( X - 1 ) = 0
D) 5 ( X + 1 ) - 3 ( X + 2 ) = 0​

Soluções para a tarefa

Respondido por Ajudant912
15

 \large \bf \rm{ \color{yellow}A) \: 7(x - 5) = 3(x + 1)}

 \bf \rm{7x - 35 = 3(x + 1)}  \\  \bf \rm7x - 35 = 3x + 3 \:  \:  \:

 \bf \rm{7x - 35 - 3x = 3} \\  \bf \rm{7x - 3x = 3 + 35}

 \bf \rm{4x = 3 + 35} \\  \bf \rm{4x = 38} \:  \:  \:  \:  \:  \:  \:

 \bf \rm{      \color{blue}\boxed{\boxed{\boxed{\color{lightblue}\large{x =  \frac{19}{2}}}}} }\\

 \bf \rm{ \color{yellow}{{B) \: 3(x - 2) = 4( - x  + 3)}}}

 \bf{3x - 6 = 4( - x + 3)} \\  \bf{3x - 6 =  - 4x + 12}

 \bf{3x - 6 + 4x = 12} \\  \bf{3x + 4x = 12 + 6}

 \bf{7x = 12 + 6} \\  \bf{7x = 18} \:  \:  \:  \:  \:  \:  \:  \:

 \bf \rm{     \color{blue}{{\boxed{\boxed{\boxed{{\color{lightblue}x =  \frac{18}{7}}}} }}} }

 \bf \rm{ \color{yellow}{C) \: 2(x + 1) - (x - 1) = 0}}

 \rm{2x + 2 - (x - 1) = 0} \\  \rm{2x + 2 - x + 1 = 0} \:  \:  \:

 \rm{x + 2 + 1 = 0} \\  \rm{x + 3 = 0} \:  \:  \:  \:  \:  \:  \:

 \bf \rm{    \color{blue}\boxed{ \boxed{\boxed{\color{lightblue}x =  - 3}}}}

 \bf \rm{ \color{yellow}{ D) \: 5(x + 1) - 3(x + 2) = 0 }}

 \rm{5x + 5 - 3(x + 2) = 0} \\  \rm{5x + 5 - 3x - 6 = 0}

 \rm{2x + 5 - 6 = 0} \\  \rm{2x - 1 = 0} \:  \:  \:  \:  \:  \:  \:

 \rm{2x = 1}

 \bf \rm{    \color{blue}\boxed{ \boxed{\boxed{\color{lightblue}x =  \frac{1}{2} }}}}


moanadias945: -Obrigadaa ❤
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