Resolva as equações: a)60x+120+50=20x-80 b)4x/2+16=2x/3+40 c)18(x+20)-60=135+10x
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Soluções para a tarefa
Resposta:
60x+120+50=20x−80
60x+=20x-8060x+120+50=20x−80
60x+170=20x−80
60x+170=20x−80
60x+170=20x-8060x+170=20x−80
60x+170−170=20x−80−170
60 x=20 x−250
60=20−250
60x=20x-25060x=20x−250
60−20=20−250−20
40=−250
=−25 sob 4 (Resposta)
b)
42+16=23+40
+4024x+16=32x+40
2+16=23+40
2+16=23+40
2x+16=+402x+16=32x+40
2+16=23+3⋅403
2+16=23+3⋅403
2x+16=2x+16=32x+33⋅40
2+16=2+3⋅403
2+16=2+3⋅403
2x+16=2x+16=32x+3⋅40
2+16=2+1203
2+16=2+1203
2x+16=2x+16=32x+120
2+16−16=2+1203−16
=18 (Resposta)
c)
18(+20)−60=135+10
-60=135+10x18(x+20)−60=135+10x
18+360−60=135+10
18+360−60=135+10
18x+=135+10x18x+360−60=135+10x
18+300=135+10
18+300=135+10
18x+300=18x+300=135+10x
18+300=10+135
18+300=10+135
18x+300=10x+13518x+300=10x+135
18+300−300=10+135−300
18=10−165
=−1658 (Resposta)